Solutions to the 65 th
نویسنده
چکیده
A1 Yes. Suppose otherwise. Then there would be an N such that S(N) < 80% and S(N + 1) > 80%; that is, O’Keal’s free throw percentage is under 80% at some point, and after one subsequent free throw (necessarily made), her percentage is over 80%. If she makes m of her first N free throws, then m/N < 4/5 and (m + 1)/(N + 1) > 4/5. This means that 5m < 4n < 5m+ 1, which is impossible since then 4n is an integer between the consecutive integers 5m and 5m+ 1.
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